tìm x biết
\(\frac{x-2}{1002}+\frac{x-4}{1001}+\frac{x-6}{1000}=\frac{x-8}{999}+\frac{x-10}{998}+\frac{x-12}{997}\)
Những câu hỏi liên quan
Tìm x,biết:
a)\(\frac{x+1}{999}+\frac{x+2}{998}=\frac{x+3}{997}+\frac{x+4}{996}\)
b)\(\frac{x+1}{1001}+\frac{x+2}{1002}=\frac{x+3}{1003}+\frac{x+4}{1004}\)
c)\(|x|-\frac{15}{2}=\frac{15}{4}\)
d)\(|\frac{3}{4}-x|+1|=\frac{3}{2}\)
.a, \(\frac{x+1}{999}+\frac{x+2}{998}=\frac{x+3}{997}+\frac{x+4}{996}\)
.\(< =>\frac{x+1}{999}+1+\frac{x+2}{998}+1=\frac{x+3}{997}+1+\frac{x+4}{996}+1\)
.\(< =>\frac{x+1}{999}+\frac{999}{999}+\frac{x+2}{998}+\frac{998}{998}=\frac{x+3}{997}+\frac{997}{997}+\frac{x+4}{996}+\frac{996}{996}\)
.\(< =>\frac{x+1+999}{999}+\frac{x+2+998}{998}=\frac{x+3+997}{997}+\frac{x+4+996}{996}\)
.\(< =>\frac{x+1000}{999}+\frac{x+1000}{998}-\frac{x+1000}{997}-\frac{x+1000}{996}=0\)
.\(< =>\left(x+1000\right)\left(\frac{1}{999}+\frac{1}{998}-\frac{1}{997}-\frac{1}{996}\right)=0\)
.Do \(\frac{1}{999}+\frac{1}{998}-\frac{1}{997}-\frac{1}{996}\ne0\)
.Suy ra \(x+1000=0\Leftrightarrow x=-1000\)
.b, \(\frac{x+1}{1001}+\frac{x+2}{1002}=\frac{x+3}{1003}+\frac{x+4}{1004}\)
.\(< =>\frac{x+1}{1001}-1+\frac{x+2}{1002}-1=\frac{x+3}{1003}-1+\frac{x+4}{1004}-1\)
.\(< =>\frac{x+1}{1001}-\frac{1001}{1001}+\frac{x+2}{1002}-\frac{1002}{1002}=\frac{x+3}{1003}-\frac{1003}{1003}+\frac{x+4}{1004}-\frac{1004}{1004}\)
.\(< =>\frac{x+1-1001}{1001}+\frac{x+2-1002}{1002}=\frac{x+3-1003}{1003}+\frac{x+4-1004}{1004}\)
.\(< =>\frac{x-1000}{1001}+\frac{x+1000}{1002}-\frac{x+1000}{1003}-\frac{x+1000}{1004}=0\)
.\(< =>\left(x-1000\right)\left(\frac{1}{1001}+\frac{1}{1002}-\frac{1}{1003}-\frac{1}{1004}\right)=0\)
.Do \(\frac{1}{1001}+\frac{1}{1002}-\frac{1}{1003}-\frac{1}{1004}\ne0\)
.Suy ra \(x-1000=0\Leftrightarrow x=1000\)
mình làm luộn 2 câu còn lại nhé ^^
.c,\(|x|-\frac{15}{2}=\frac{15}{4}\)
.\(< =>|x|=\frac{15}{4}+\frac{15}{2}=\frac{15}{4}+\frac{30}{4}=\frac{45}{4}\)
.\(< =>\orbr{\begin{cases}x=\frac{45}{4}\\x=-\frac{45}{4}\end{cases}}\)
.d,\(|\frac{3}{4}-x|+1=\frac{3}{2}\)
.\(< =>|\frac{3}{4}-x|=\frac{3}{2}-1=\frac{3}{2}-\frac{2}{2}=\frac{1}{2}\)
.\(< =>\orbr{\begin{cases}\frac{3}{4}-x=\frac{1}{2}\\\frac{3}{4}-x=-\frac{1}{2}\end{cases}< =>\orbr{\begin{cases}x=\frac{3}{4}-\frac{1}{2}=\frac{1}{4}\\x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\end{cases}}}\)
Giải các phương trình sau
\(a.\frac{x+1006}{1000}+\frac{x+1007}{999}+\frac{x+1008}{998}+\frac{x+1009}{997}+\frac{x+2022}{4}=0\)
\(b.\frac{x-999}{99}+\frac{x-896}{101}+\frac{x-769}{103}=6\)
GIẢI HỘ MK NHÉ. CÂU NÀO CX ĐC! <3
a, \(\frac{x+1006}{1000}+\frac{x+1007}{999}+\frac{x+1008}{998}+\frac{x+1009}{997}+\frac{x+2022}{4}=0\)
\(\Leftrightarrow\frac{x+1006}{1000}+1+\frac{x+1007}{999}+1+\frac{x+1008}{998}+1+\frac{x+1009}{997}+1+\frac{x+2022}{4}-4=0\)
\(\Leftrightarrow\frac{x+2006}{1000}+\frac{x+2006}{999}+\frac{x+2006}{998}+\frac{x+2006}{997}+\frac{x+2006}{4}=0\)
\(\Leftrightarrow\left(x+2006\right)\left(\frac{1}{1000}+\frac{1}{999}+\frac{1}{998}+\frac{1}{997}+\frac{1}{4}\right)=0\)
Mà \(\frac{1}{1000}+\frac{1}{999}+\frac{1}{998}+\frac{1}{997}+\frac{1}{4}\ne0\)
\(\Rightarrow x+2006=0\Leftrightarrow x=-2006\)
Đúng 0
Bình luận (0)
Tính giá trị biểu thức bằng cách thuận tiện nhất:a) frac{3^4-1^2}{4^3-2^1}+frac{7^8-5^6}{8^7-6^5}+...+frac{995^{996}-993^{994}}{996^{995}-994^{993}}+frac{999^{1000}-997^{998}}{1000^{999}-998^{997}}b)frac{4^3}{3^4}-frac{2^1}{1^2}+frac{8^7}{7^8}-frac{6^5}{5^6}+...+frac{996^{995}}{995^{996}}-frac{994^{993}}{993^{994}}+frac{1000^{999}}{999^{1000}}-frac{998^{997}}{997^{998}}c)frac{3^4}{4^3}-frac{1^2}{2^1}+frac{7^8}{8^7}-frac{5^6}{6^5}+...+frac{995^{996}}{996^{995}}-frac{993^{994}}{994^{993}}+frac{999...
Đọc tiếp
Tính giá trị biểu thức bằng cách thuận tiện nhất:
a) \(\frac{3^4-1^2}{4^3-2^1}+\frac{7^8-5^6}{8^7-6^5}+...+\frac{995^{996}-993^{994}}{996^{995}-994^{993}}+\frac{999^{1000}-997^{998}}{1000^{999}-998^{997}}\)
b)\(\frac{4^3}{3^4}-\frac{2^1}{1^2}+\frac{8^7}{7^8}-\frac{6^5}{5^6}+...+\frac{996^{995}}{995^{996}}-\frac{994^{993}}{993^{994}}+\frac{1000^{999}}{999^{1000}}-\frac{998^{997}}{997^{998}}\)
c)\(\frac{3^4}{4^3}-\frac{1^2}{2^1}+\frac{7^8}{8^7}-\frac{5^6}{6^5}+...+\frac{995^{996}}{996^{995}}-\frac{993^{994}}{994^{993}}+\frac{999^{1000}}{1000^{999}}-\frac{997^{998}}{998^{997}}\)
Không sao đâu,các bạn có thể giải từng câu một nhưng phải nhanh lên nhé!
(Các bạn nhớ ghi cách làm nhé!)
:)) ko bt làm :))
kí tên
cái nịt
\(\frac{x+4}{996}+\frac{x+3}{997}+\frac{x+2}{998}+\frac{x+1}{999}=4\)
Mọi người giúp mình với nhé ! thank !
tìm x biết
\(\frac{26-x}{995}+\frac{22-x}{997}+\frac{18-x}{999}=\)\(\frac{12-x}{334}\)
nhanh nha mấy chế !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
\(\frac{26-x}{995}\)+2+\(\frac{22-x}{997}\)+\(\frac{18-x}{999}\)+2=\(\frac{12-x}{334}\)+6
\(\frac{2016-x}{995.2}\)+\(\frac{2016-x}{997.2}\)+\(\frac{2016-x}{999.2}\)-\(\frac{2016-x}{334.6}\)=0
(2016-x)(\(\frac{1}{995.2}\)+\(\frac{1}{997.2}\)\(\frac{1}{999.2}\)-\(\frac{1}{334.6}\))=0
Dễ thấy giá trị biểu thức trong ngoặc thứ 2 khác 0
Nên 2016-x=0=>x=2016
Vậy giá trị của x là 2016
Đúng 0
Bình luận (0)
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{998}{1000}\)
tìm x nhé
\(\Rightarrow\frac{1}{2}\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}\right)=\frac{1}{2}\cdot\frac{998}{1000}\)
\(\Rightarrow\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{x\left(x+1\right)}=\frac{499}{1000}\)
\(\Rightarrow\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x\left(x+1\right)}=\frac{499}{1000}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{499}{1000}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{499}{1000}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{2}-\frac{499}{1000}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{1000}\)
=>x+1=1000
=>x=999
Đúng 0
Bình luận (0)
Tìm x , biết : \(\frac{25-x}{995}+\frac{21-x}{997}+\frac{17-x}{999}=\frac{11-x}{334}\)
\(\frac{25-x}{995}+\frac{21-x}{997}+\frac{17-x}{999}=\frac{11-x}{334}\)
\(\Rightarrow\frac{25-x}{995}+2+\frac{21-x}{997}+\frac{17-x}{999}+2=\frac{11-x}{334}+6\)
\(\Rightarrow\frac{25-x}{995}+\frac{1990}{995}+\frac{21-x}{997}+\frac{1994}{997}+\frac{17-x}{999}+\frac{1998}{999}=\frac{11-x}{334}+\frac{2004}{334}\)
\(\Rightarrow\frac{2015-x}{995}+\frac{2015-x}{997}+\frac{2015-x}{999}=\frac{2015-x}{334}\)
\(\Rightarrow\frac{2015-x}{995}+\frac{2015-x}{997}+\frac{2015-x}{999}-\frac{2015-x}{334}=0\)
\(\Rightarrow\left(2015-x\right)\left(\frac{1}{995}+\frac{1}{997}+\frac{1}{999}+\frac{1}{334}\right)=0\)
\(\Rightarrow2015-x=0\left(\text{vì }\frac{1}{995}+\frac{1}{997}+\frac{1}{999}+\frac{1}{334}\ne0\right)\)
\(\Rightarrow x=2015\)
Đúng 1
Bình luận (0)
Tìm x biết
a) x+2x+3x+4x+...+100x=-213
b)\(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
c)3(x-2)+2(x-1)=10
d)\(\frac{x+1}{3}=\frac{x-2}{4}\)
e)\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
f)\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
#)Giải :
a) x + 2x + 3x + ... + 100x = - 213
=> 100x + ( 2 + 3 + 4 + ... + 100 ) = - 213
=> 100x + 5049 = - 213
<=> 100x = - 5262
<=> x = - 52,62
Đúng 0
Bình luận (0)
#)Giải :
b) \(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
\(\Rightarrow\frac{1}{2}x+\frac{1}{4}x=\frac{1}{3}+\frac{1}{6}\)
\(\Rightarrow\frac{1}{2}x+\frac{1}{4}x=\frac{1}{2}\)
\(\Rightarrow\left(\frac{1}{2}+\frac{1}{4}\right)x=\frac{1}{2}\)
\(\Rightarrow\frac{3}{4}x=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{2}{3}\)
Đúng 0
Bình luận (0)
a) x + 2x + 3x + ... +100x = -213
=> x . (1 + 2 + 3 +... + 100) = - 213
=> x . 5050 = -213
=> x = - 213 : 5050
=> x = -213/5050
b) \(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
=> \(\frac{1}{2}x-\frac{1}{4}x=\frac{1}{3}-\frac{1}{6}\)
=> \(x.\left(\frac{1}{2}-\frac{1}{4}\right)=\frac{1}{6}\)
=> \(x.\frac{1}{4}=\frac{1}{6}\)
=> \(x=\frac{1}{6}:\frac{1}{4}\)
=> \(x=\frac{2}{3}\)
c) 3(x-2) + 2(x-1) = 10
=> 3x - 6 + 2x - 2 = 10
=> 3x + 2x - 6 - 2 = 10
=> 5x - 8 = 10
=> 5x = 10 + 8
=> 5x = 18
=> x = 18:5
=> x = 3,6
d) \(\frac{x+1}{3}=\frac{x-2}{4}\)
=> \(4\left(x+1\right)=3\left(x-2\right)\)
=>\(4x+4=3x-6\)
=> \(4x-3x=-4-6\)
=> \(x=-10\)
Đúng 0
Bình luận (0)
Tìm x, biết: \(\frac{x+2}{17}+\frac{x+4}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}+\frac{x+12}{7}\)
(x+2)/17+(x+4)/15+(x+6)/13=(x+8)/11+(x+10)/9+(x+12)/7
=>(x+2+17)/17+(x+4+15)/15+(x+6+13)/13=(x+8+11)/11+(x+10+9)/9+(x+12+7)/7
=>(x+19)/17+(x+19)/15+(x+19)/13=(x+19)/11+(x+19)/9+(x+19)/7
=>(x+19)/17+(x+19)/15+(x+19)/13-(x+19)/11-(x+19)/9-(x+19)/7=0
=>(x+19)*(1/17+1/15+1/13-1/11-1/9-1/7)=0
=>x+19=0
=>x=19
Đúng 0
Bình luận (0)
áp dụng tc tỉ lệ thức ta có :
\(\Leftrightarrow\frac{671x+2804}{3315}=\frac{239x+2462}{693}\Rightarrow\left(671x+2804\right)693=3315\left(239x+2462\right)\)
=>(671x+2804)693=693(671x+2804) (VT)
<=>693(671x+2804)=3315(239x+2462)
=>465003x+1943172=792285x+8161530
=>-327282x=621835
=>x=621835:(-327282)
=>x=-19
Đúng 0
Bình luận (0)